介绍

给定两个字符串，以另一种方式合并它们，即最终字符串的第一个字符是第一个字符串的第一个字符，最终字符串的第二个字符是第二个字符串的第一个字符，以此类推。如果你达到了一个字符串的末尾，而另一个字符串还在，那么就把这个字符串的剩余部分追加到最后一个字符串中。

实现

JavaScript

// Alternative arrange the two given strings in one string in O(n) time complexity.


// Problem Source & Explanation: https://www.geeksforgeeks.org/alternatively-merge-two-strings-in-java/

/**
 * Alternative arrange the two given strings in one string in O(n) time complexity.
 * @param {String} str1 first input string
 * @param {String} str2 second input string
 * @returns `String` return one alternative arrange string.
 */
const AlternativeStringArrange = (str1, str2) => {
  // firstly, check that both inputs are strings.
  if (typeof str1 !== 'string' || typeof str2 !== 'string') {
    return 'Not string(s)'
  }

  // output string value.
  let outStr = ''

  // get first string length.
  const firstStringLength = str1.length
  // get second string length.
  const secondStringLength = str2.length
  // absolute length for operation.
  const absLength = firstStringLength > secondStringLength ? firstStringLength : secondStringLength

  // Iterate the character count until the absolute count is reached.
  for (let charCount = 0; charCount < absLength; charCount++) {
    // If firstStringLength is lesser than the charCount it means they are able to re-arrange.
    if (charCount < firstStringLength) {
      outStr += str1[charCount]
    }

    // If secondStringLength is lesser than the charCount it means they are able to re-arrange.
    if (charCount < secondStringLength) {
      outStr += str2[charCount]
    }
  }

  // return the output string.
  return outStr
}

参考

• Alternatively Merge two Strings in Java - GeeksforGeeks (opens new window)